What is the extreme f(x)= 1/3 x^3-2x^2-5x-10 ?

The extreme f(x)= 1/3 x^3-2x^2-5x-10 is Maximum(-1,-22/3),Minimum(5,-130/3)

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extreme f(x)= 1/3 x^3-2x^2-5x-10

extreme points

f (x) = \frac{1}{3} x^{3} - 2 x^{2} - 5 x - 10

Maximum (- 1, - \frac{22}{3}), Minimum (5, - \frac{130}{3})

Solution steps

f^{'} (x) = x^{2} - 4 x - 5

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = - 1

into

\frac{1}{3} x^{3} - 2 x^{2} - 5 x - 10 : - \frac{22}{3}

Maximum (- 1, - \frac{22}{3})

Plug

x = 5

into

\frac{1}{3} x^{3} - 2 x^{2} - 5 x - 10 : - \frac{130}{3}

Minimum (5, - \frac{130}{3})

Maximum (- 1, - \frac{22}{3}), Minimum (5, - \frac{130}{3})

f (x) = 3 - x^{\frac{4}{5}}

f (x) = 2 x e^{- y}

f (x) = 8 (1 + \frac{1}{x} + \frac{1}{x ^{2}})

f (x) = 2 x^{3} + 6 x^{2} - 48 x + 7

x^{4} - 5 x^{2}

What is the extreme f(x)= 1/3 x^3-2x^2-5x-10 ?
The extreme f(x)= 1/3 x^3-2x^2-5x-10 is Maximum(-1,-22/3),Minimum(5,-130/3)