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Popular >

extreme f(x)=x^{8/9}-3

Solution

extreme points

f (x) = x^{\frac{8}{9}} - 3

Solution

Minimum (0, - 3)

Solution steps

f^{'} (x) = \frac{8}{9 x ^{\frac{1}{9}}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{\frac{8}{9}} - 3 : - 3

Minimum (0, - 3)

Popular Examples

extreme f(x)=x^3-3x^2+3x+7 extreme points

f (x) = x^{3} - 3 x^{2} + 3 x + 7

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f (x) = (t - 4 t^{2})^{\frac{1}{3}}

extreme f(x,y)=1-(x^2+y^2)extreme points

f (x, y) = 1 - (x^{2} + y^{2})

extreme x/((x^2+1))extreme points

\frac{x}{( x ^{2} + 1 )}

extreme f(x)=x^3-3x^2+3x-1 extreme points

f (x) = x^{3} - 3 x^{2} + 3 x - 1

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^{8/9}-3 ?
The extreme f(x)=x^{8/9}-3 is Minimum(0,-3)