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Popular >

extreme (3x+2)(2x+5)

Solution

extreme points

(3 x + 2) (2 x + 5)

Solution

Minimum (- \frac{19}{12}, - \frac{121}{24})

Solution steps

f^{'} (x) = 12 x + 19

Find intervals:

Decreasing

: - \infty < x < - \frac{19}{12},

Increasing

: - \frac{19}{12} < x < \infty

Plug

x = - \frac{19}{12}

into

(3 x + 2) (2 x + 5) : - \frac{121}{24}

Minimum (- \frac{19}{12}, - \frac{121}{24})

Popular Examples

extreme f(x)=-4/(x-5)extreme points

f (x) = - \frac{4}{x - 5}

extreme 2x^2+(36)/x extreme points

2 x^{2} + \frac{36}{x}

extreme f(x)=-4/(x-7)extreme points

f (x) = - \frac{4}{x - 7}

extreme f(x)=4-sqrt(9-x)extreme points

f (x) = 4 - 9 - x

extreme f(x)=x^6-2x^5+8x^4 extreme points

f (x) = x^{6} - 2 x^{5} + 8 x^{4}

Frequently Asked Questions (FAQ)

What is the extreme (3x+2)(2x+5) ?
The extreme (3x+2)(2x+5) is Minimum(-19/12 ,-121/24)