What is the extreme f(x)=310x^2-1860x^3 ?

The extreme f(x)=310x^2-1860x^3 is Minimum(0,0),Maximum(1/9 , 310/243)

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extreme f(x)=310x^2-1860x^3

extreme points

f (x) = 310 x^{2} - 1860 x^{3}

Minimum (0, 0), Maximum (\frac{1}{9}, \frac{310}{243})

Solution steps

f^{'} (x) = 620 x - 5580 x^{2}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \frac{1}{9},

Decreasing

: \frac{1}{9} < x < \infty

Plug

x = 0

into

310 x^{2} - 1860 x^{3} : 0

Minimum (0, 0)

Plug

x = \frac{1}{9}

into

310 x^{2} - 1860 x^{3} : \frac{310}{243}

Maximum (\frac{1}{9}, \frac{310}{243})

Minimum (0, 0), Maximum (\frac{1}{9}, \frac{310}{243})

f (x) = x^{2} + y^{2} + 4 x - 2 y + 6

f (x) = \frac{8 x ^{2}}{x + 1}, (- 1, 5)

8 x^{3} + 75 x^{2} - 336 x + 7

f (x) = 2 x^{4} + x^{3} - 15 x^{2} - 9 x - 27

f (x) = x^{2} + 4 x + 7

What is the extreme f(x)=310x^2-1860x^3 ?
The extreme f(x)=310x^2-1860x^3 is Minimum(0,0),Maximum(1/9 , 310/243)