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Popular >

extreme f(x)=x^3+6x^2+12x+3

Solution

extreme points

f (x) = x^{3} + 6 x^{2} + 12 x + 3

Solution

Saddle (- 2, - 5)

Solution steps

f^{'} (x) = 3 x^{2} + 12 x + 12

Find intervals:

Increasing

: - \infty < x < - 2,

Increasing

: - 2 < x < \infty

Plug

x = - 2

into

x^{3} + 6 x^{2} + 12 x + 3 : - 5

Saddle (- 2, - 5)

Popular Examples

extreme f(x)=7x^4-28x^3+5 extreme points

f (x) = 7 x^{4} - 28 x^{3} + 5

extreme f(x)=x^4-24^2+180 extreme points

f (x) = x^{4} - 2 4^{2} + 180

extreme f(x)=2x^4-16x^3 extreme points

f (x) = 2 x^{4} - 16 x^{3}

extreme f(x)=x^2-8x,0<= x<= 9 extreme points

f (x) = x^{2} - 8 x, 0 \leq x \leq 9

extreme f(x)=2-3x,0<= x<= 1 extreme points

f (x) = 2 - 3 x, 0 \leq x \leq 1

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^3+6x^2+12x+3 ?
The extreme f(x)=x^3+6x^2+12x+3 is Saddle(-2,-5)