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Popular >

extreme y=x^2-11x+30

Solution

extreme points

y = x^{2} - 11 x + 30

Solution

Minimum (\frac{11}{2}, - \frac{1}{4})

Solution steps

f^{'} (x) = 2 x - 11

Find intervals:

Decreasing

: - \infty < x < \frac{11}{2},

Increasing

: \frac{11}{2} < x < \infty

Plug

x = \frac{11}{2}

into

x^{2} - 11 x + 30 : - \frac{1}{4}

Minimum (\frac{11}{2}, - \frac{1}{4})

Graph

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Frequently Asked Questions (FAQ)

What is the extreme y=x^2-11x+30 ?
The extreme y=x^2-11x+30 is Minimum(11/2 ,-1/4)