What is the extreme f(x,y)=9-2x+8y-x^2-4y^2 ?

The extreme f(x,y)=9-2x+8y-x^2-4y^2 is Maximum(-1,1)

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extreme f(x,y)=9-2x+8y-x^2-4y^2

extreme points

f (x, y) = 9 - 2 x + 8 y - x^{2} - 4 y^{2}

Maximum (- 1, 1)

Solution steps

Find the critical points:

(- 1, 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 8

D (x, y) = 16

Check the sign of at each critical point

Check critical point

(- 1, 1) :

Maximum

Maximum (- 1, 1)

f (x) = - 4 x^{5} ln (2 x)

f (x) = \frac{x ^{3}}{x} - 3 x^{2} - 7 x

y = x^{3} + 3 x^{2} + 3 x + 1

f (x) = \frac{8 x - 3}{x}

1 + \frac{7}{x} - \frac{5}{x ^{2}}

What is the extreme f(x,y)=9-2x+8y-x^2-4y^2 ?
The extreme f(x,y)=9-2x+8y-x^2-4y^2 is Maximum(-1,1)