What is the extreme f(x)=200x-(0.003x^2+80x+500000) ?

The extreme f(x)=200x-(0.003x^2+80x+500000) is Maximum(20000,700000)

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extreme f(x)=200x-(0.003x^2+80x+500000)

extreme points

f (x) = 200 x - (0.003 x^{2} + 80 x + 500000)

Maximum (20000, 700000)

Solution steps

f^{'} (x) = - 0.006 x + 120

Find intervals:

Increasing

: - \infty < x < 20000,

Decreasing

: 20000 < x < \infty

Plug

x = 20000

into

200 x - (0.003 x^{2} + 80 x + 500000) : 700000

Maximum (20000, 700000)

- \frac{\frac{40}{3}}{x ^{2}} + 0.54 x

f (x, y) = x \cdot e^{y}

f (x) = 4 θ - 6 sin (θ)

f (x, y) = x^{2} + y^{2} - 2 x + y

f (x) = 2 x^{3} + 9 x^{2} - 24 x - 10

What is the extreme f(x)=200x-(0.003x^2+80x+500000) ?
The extreme f(x)=200x-(0.003x^2+80x+500000) is Maximum(20000,700000)