What is the extreme f(x)=(25x^2+81)/x ?

The extreme f(x)=(25x^2+81)/x is Maximum(-9/5 ,-90),Minimum(9/5 ,90)

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extreme f(x)=(25x^2+81)/x

extreme points

f (x) = \frac{25 x ^{2} + 81}{x}

Maximum (- \frac{9}{5}, - 90), Minimum (\frac{9}{5}, 90)

Solution steps

f^{'} (x) = \frac{25 x ^{2} - 81}{x ^{2}}

Find intervals:

Increasing

: - \infty < x < - \frac{9}{5},

Decreasing

: - \frac{9}{5} < x < 0,

Decreasing

: 0 < x < \frac{9}{5},

Increasing

: \frac{9}{5} < x < \infty

Plug

x = - \frac{9}{5}

into

\frac{25 x ^{2} + 81}{x} : - 90

Maximum (- \frac{9}{5}, - 90)

Plug

x = \frac{9}{5}

into

\frac{25 x ^{2} + 81}{x} : 90

Minimum (\frac{9}{5}, 90)

Maximum (- \frac{9}{5}, - 90), Minimum (\frac{9}{5}, 90)

K (y, z) = 4 yz

f (x) = 5 x^{3} e^{- 0.9 x}, - 1 \leq x \leq 5

f (x) = x^{4} - 98 x^{2} + 11, - 6 \leq x \leq 15

f (x) = - 2 x^{2} + 8 x + 13

f (x) = x^{3} - 27 x^{2} + 216 x

What is the extreme f(x)=(25x^2+81)/x ?
The extreme f(x)=(25x^2+81)/x is Maximum(-9/5 ,-90),Minimum(9/5 ,90)