What is the extreme s(t)=-4.9t^2+29t+2 ?

The extreme s(t)=-4.9t^2+29t+2 is Maximum(145/49 ,44.90816…)

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extreme s(t)=-4.9t^2+29t+2

extreme points

s (t) = - 4.9 t^{2} + 29 t + 2

Maximum (\frac{145}{49}, 44.90816 \dots)

Solution steps

f^{'} (t) = - 9.8 t + 29

Find intervals:

Increasing

: - \infty < t < \frac{145}{49},

Decreasing

: \frac{145}{49} < t < \infty

Plug

t = \frac{145}{49}

into

- 4.9 t^{2} + 29 t + 2 : 44.90816 \dots

Maximum (\frac{145}{49}, 44.90816 \dots)

y = (x + 3)^{2} - 7

f (x) = 3 x - \frac{1}{2} x^{2} - \frac{1}{2} ln (x)

f (x) = 20.85 x y + 10.7 x^{2} + 51.75 y^{2}

x^{5} - x^{3}

f (x) = 6 sin (2 x)

What is the extreme s(t)=-4.9t^2+29t+2 ?
The extreme s(t)=-4.9t^2+29t+2 is Maximum(145/49 ,44.90816…)