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Popular >

extreme y=x^3+3x^2+1

Solution

extreme points

y = x^{3} + 3 x^{2} + 1

Solution

Maximum (- 2, 5), Minimum (0, 1)

Solution steps

f^{'} (x) = 3 x^{2} + 6 x

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 2

into

x^{3} + 3 x^{2} + 1 : 5

Maximum (- 2, 5)

Plug

x = 0

into

x^{3} + 3 x^{2} + 1 : 1

Minimum (0, 1)

Maximum (- 2, 5), Minimum (0, 1)

Popular Examples

extreme f(x)=-4x^3-3x^2+6x+1 extreme points

f (x) = - 4 x^{3} - 3 x^{2} + 6 x + 1

extreme 150(xy)^2+(0.5x+2y-2)^2 extreme points

150 (x y)^{2} + (0.5 x + 2 y - 2)^{2}

extreme 3x^2-5x-1 extreme points

3 x^{2} - 5 x - 1

extreme f(x,y)=x^2-5yx+3y^2 extreme points

f (x, y) = x^{2} - 5 y x + 3 y^{2}

extreme y=((2x+3))/(x+2)extreme points

y = \frac{( 2 x + 3 )}{x + 2}

Frequently Asked Questions (FAQ)

What is the extreme y=x^3+3x^2+1 ?
The extreme y=x^3+3x^2+1 is Maximum(-2,5),Minimum(0,1)