What is the extreme f(x,y)=x^2-5yx+3y^2 ?

The extreme f(x,y)=x^2-5yx+3y^2 is Saddle(0,0)

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extreme f(x,y)=x^2-5yx+3y^2

extreme points

f (x, y) = x^{2} - 5 y x + 3 y^{2}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = 6

D (x, y) = - 13

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

y = \frac{( 2 x + 3 )}{x + 2}

f (x) = \frac{x ^{2} - 5 x + 7}{x - 3}

f (x) = (3 x^{3} - 9)

f (x) = \frac{x ^{2} - 4}{e ^{x^{4} - 1}}

f (x) = 2 x - 5 x^{2} + 4

What is the extreme f(x,y)=x^2-5yx+3y^2 ?
The extreme f(x,y)=x^2-5yx+3y^2 is Saddle(0,0)