What is the extreme f(x)=-(4/(x^2)),(-3,-1) ?

The extreme f(x)=-(4/(x^2)),(-3,-1) is None

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extreme f(x)=-(4/(x^2)),(-3,-1)

extreme points

f (x) = - (\frac{4}{x ^{2}}), (- 3, - 1)

None

Solution steps

Find the critical points:

None

- \frac{4}{x ^{2}}

has no critical points, therefore there are no extreme points

None

f (x) = 4 - x^{3} + 5 x

f (x) = 2 x^{3} - 6 x + 11

f (x) = sin (5 x), 0 \leq x \leq \frac{2 π}{5}

y = 16 x^{4} + 64 x^{3}

3 x^{2} - 2 x y + y^{2} - 8 y

What is the extreme f(x)=-(4/(x^2)),(-3,-1) ?
The extreme f(x)=-(4/(x^2)),(-3,-1) is None