What is the extreme f(x)=2x^3-(12x^2)/2-2[-1.3] ?

The extreme f(x)=2x^3-(12x^2)/2-2[-1.3] is Maximum(0,2.6),Minimum(2,-5.4)

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extreme f(x)=2x^3-(12x^2)/2-2[-1.3]

extreme points

f (x) = 2 x^{3} - \frac{12 x ^{2}}{2} - 2 [- 1.3]

Maximum (0, 2.6), Minimum (2, - 5.4)

Solution steps

f^{'} (x) = 6 x^{2} - 12 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 0

into

2 x^{3} - \frac{12 x ^{2}}{2} - 2 [- 1.3] : 2.6

Maximum (0, 2.6)

Plug

x = 2

into

2 x^{3} - \frac{12 x ^{2}}{2} - 2 [- 1.3] : - 5.4

Minimum (2, - 5.4)

Maximum (0, 2.6), Minimum (2, - 5.4)

\frac{27 x ^{2}}{( 2 - x ) ^{3}}

\frac{8 x ^{2}}{x - 6}, - 3 \leq x \leq 2

f (x, y) = x + 3 y

g (x) = x^{3} - 12 x^{2} + 45 x + 4

g (x) = x^{3} - 12 x^{2} + 45 x + 1

What is the extreme f(x)=2x^3-(12x^2)/2-2[-1.3] ?
The extreme f(x)=2x^3-(12x^2)/2-2[-1.3] is Maximum(0,2.6),Minimum(2,-5.4)