What is the extreme g(x)=x^3-12x^2+45x+1 ?

The extreme g(x)=x^3-12x^2+45x+1 is Maximum(3,55),Minimum(5,51)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme g(x)=x^3-12x^2+45x+1

extreme points

g (x) = x^{3} - 12 x^{2} + 45 x + 1

Maximum (3, 55), Minimum (5, 51)

Solution steps

f^{'} (x) = 3 x^{2} - 24 x + 45

Find intervals:

Increasing

: - \infty < x < 3,

Decreasing

: 3 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = 3

into

x^{3} - 12 x^{2} + 45 x + 1 : 55

Maximum (3, 55)

Plug

x = 5

into

x^{3} - 12 x^{2} + 45 x + 1 : 51

Minimum (5, 51)

Maximum (3, 55), Minimum (5, 51)

g (x) = x^{3} - 12 x^{2} + 45 x + 2

g (x) = x^{3} - 12 x^{2} + 45 x + 7

f (x) = - 2 - 3 x + x^{2}

f (x) = \frac{( x ^{2} - 1 )}{x ^{2} + 2 x - 3}

f (x) = - 3 t^{2} + 72 t + 243

What is the extreme g(x)=x^3-12x^2+45x+1 ?
The extreme g(x)=x^3-12x^2+45x+1 is Maximum(3,55),Minimum(5,51)