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Popular >

extreme f(x)=-2-3x+x^2

Solution

extreme points

f (x) = - 2 - 3 x + x^{2}

Solution

Minimum (\frac{3}{2}, - \frac{17}{4})

Solution steps

f^{'} (x) = 2 x - 3

Find intervals:

Decreasing

: - \infty < x < \frac{3}{2},

Increasing

: \frac{3}{2} < x < \infty

Plug

x = \frac{3}{2}

into

- 2 - 3 x + x^{2} : - \frac{17}{4}

Minimum (\frac{3}{2}, - \frac{17}{4})

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=-2-3x+x^2 ?
The extreme f(x)=-2-3x+x^2 is Minimum(3/2 ,-17/4)