What is the extreme f(x)=-25x^2-20y^2+300x+480y+200 ?

The extreme f(x)=-25x^2-20y^2+300x+480y+200 is Maximum(6,12)

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extreme f(x)=-25x^2-20y^2+300x+480y+200

extreme points

f (x) = - 25 x^{2} - 20 y^{2} + 300 x + 480 y + 200

Maximum (6, 12)

Solution steps

Find the critical points:

(6, 12)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 40

D (x, y) = 2000

Check the sign of at each critical point

Check critical point

(6, 12) :

Maximum

Maximum (6, 12)

24 x^{3} - 3 x^{4} - x^{3} (24 - 3 x)

y = 9 x + 9 sin (x), 0 \leq x \leq 2 π

f (x) = 5 x^{2} - 10 x + 2

f (x) = 5 x^{2} - 10 x + 8

f (x) = 8 x^{2} + 20 x + 8, 1 \leq x \leq 3

What is the extreme f(x)=-25x^2-20y^2+300x+480y+200 ?
The extreme f(x)=-25x^2-20y^2+300x+480y+200 is Maximum(6,12)