What is the extreme 20-0.06x+0.0002x^2 ?

The extreme 20-0.06x+0.0002x^2 is Minimum((0.06)/(0.0004),15.5)

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extreme 20-0.06x+0.0002x^2

extreme points

20 - 0.06 x + 0.0002 x^{2}

Minimum (\frac{0.06}{0.0004}, 15.5)

Solution steps

f^{'} (x) = 0.0004 x - 0.06

Find intervals:

Decreasing

: - \infty < x < \frac{0.06}{0.0004},

Increasing

: \frac{0.06}{0.0004} < x < \infty

Plug

x = \frac{0.06}{0.0004}

into

20 - 0.06 x + 0.0002 x^{2} : 15.5

Minimum (\frac{0.06}{0.0004}, 15.5)

f (x) = 2 x - 5 x^{2}

2 x^{2} - 4 x + 1

f (x) = y^{2} + y^{2} \cdot x + 3 x - 8

x e^{\frac{- x ^{2}}{162}}, - 4 \leq x \leq 18

f (x) = 2 x^{3} - 9 x^{2} - 24 x + 6, - 2 \leq x \leq 5

What is the extreme 20-0.06x+0.0002x^2 ?
The extreme 20-0.06x+0.0002x^2 is Minimum((0.06)/(0.0004),15.5)