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Popular >

extreme 2x^2-4x+1

Solution

extreme points

2 x^{2} - 4 x + 1

Solution

Minimum (1, - 1)

Solution steps

f^{'} (x) = 4 x - 4

Find intervals:

Decreasing

: - \infty < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

2 x^{2} - 4 x + 1 : - 1

Minimum (1, - 1)

Popular Examples

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f (x) = y^{2} + y^{2} \cdot x + 3 x - 8

extreme xe^{(-x^2)/(162)},-4<= x<= 18 extreme points

x e^{\frac{- x ^{2}}{162}}, - 4 \leq x \leq 18

extreme f(x)=2x^3-9x^2-24x+6,-2<= x<= 5 extreme points

f (x) = 2 x^{3} - 9 x^{2} - 24 x + 6, - 2 \leq x \leq 5

extreme f(x,y)=(x^2-1)(y^2+y)extreme points

f (x, y) = (x^{2} - 1) (y^{2} + y)

extreme ln(x^2+7)extreme points

ln (x^{2} + 7)

Frequently Asked Questions (FAQ)

What is the extreme 2x^2-4x+1 ?
The extreme 2x^2-4x+1 is Minimum(1,-1)