What is the extreme f(x)=4+8x+128x^{-1} ?

The extreme f(x)=4+8x+128x^{-1} is Maximum(-4,-60),Minimum(4,68)

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extreme f(x)=4+8x+128x^{-1}

extreme points

f (x) = 4 + 8 x + 128 x^{- 1}

Maximum (- 4, - 60), Minimum (4, 68)

Solution steps

f^{'} (x) = - \frac{128}{x ^{2}} + 8

Find intervals:

Increasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < 0,

Decreasing

: 0 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 4

into

4 + 8 x + 128 x^{- 1} : - 60

Maximum (- 4, - 60)

Plug

x = 4

into

4 + 8 x + 128 x^{- 1} : 68

Minimum (4, 68)

Maximum (- 4, - 60), Minimum (4, 68)

f (x) = 4 x^{5} - 25 x^{4} - 40 x^{3} + 2

x^{3} + x^{2} - 5 x + 1

f (x) = 3.6 x^{5} + 4 x^{3} - 3.7 x, 0 \leq x \leq 1

ln (x^{2} + 4)

f (x) = x^{4} - 32 x^{2} + 10

What is the extreme f(x)=4+8x+128x^{-1} ?
The extreme f(x)=4+8x+128x^{-1} is Maximum(-4,-60),Minimum(4,68)