What is the extreme f(x)=x^4-32x^2-10 ?

The extreme f(x)=x^4-32x^2-10 is Minimum(-4,-266),Maximum(0,-10),Minimum(4,-266)

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extreme f(x)=x^4-32x^2-10

extreme points

f (x) = x^{4} - 32 x^{2} - 10

Minimum (- 4, - 266), Maximum (0, - 10), Minimum (4, - 266)

Solution steps

f^{'} (x) = 4 x^{3} - 64 x

Find intervals:

Decreasing

: - \infty < x < - 4,

Increasing

: - 4 < x < 0,

Decreasing

: 0 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 4

into

x^{4} - 32 x^{2} - 10 : - 266

Minimum (- 4, - 266)

Plug

x = 0

into

x^{4} - 32 x^{2} - 10 : - 10

Maximum (0, - 10)

Plug

x = 4

into

x^{4} - 32 x^{2} - 10 : - 266

Minimum (4, - 266)

Minimum (- 4, - 266), Maximum (0, - 10), Minimum (4, - 266)

f (x, y) = x - 5 y

f (x) = x^{4} (x - 5) + 4

f (x) = x^{2} - \frac{54}{x}

y = \frac{1}{9} [\frac{t ^{3}}{3} + \frac{3 t ^{2}}{2} - 28 t]

2 x^{3} + 3 x^{2} - 36 x + 3, - 3 \leq x \leq 6

What is the extreme f(x)=x^4-32x^2-10 ?
The extreme f(x)=x^4-32x^2-10 is Minimum(-4,-266),Maximum(0,-10),Minimum(4,-266)