What is the extreme f(x)=-x-4,-4<= x<= 1 ?

The extreme f(x)=-x-4,-4<= x<= 1 is Maximum(-4,0),Minimum(1,-5)

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extreme f(x)=-x-4,-4<= x<= 1

extreme points

f (x) = - x - 4, - 4 \leq x \leq 1

Maximum (- 4, 0), Minimum (1, - 5)

Solution steps

Find the critical points:

x = - 4, x = 1

Domain of

- x - 4, - 4 \leq x \leq 1 : - 4 \leq x \leq 1

Find intervals:

Decreasing

: - 4 < x < 1

Plug the extreme point

x = - 4

into

- x - 4 \Rightarrow y = 0

Maximum (- 4, 0)

Plug the extreme point

x = 1

into

- x - 4 \Rightarrow y = - 5

Minimum (1, - 5)

Maximum (- 4, 0), Minimum (1, - 5)

f (x, y) = x^{2} - 9 x y - y^{2}

x θ

f (x) = 6 x^{3} - 18 x - 4

f (x, y) = e^{x + y + 8}

f (x, y) = 2 x^{2} + 2 x y + y^{2} + 2 x - 4

What is the extreme f(x)=-x-4,-4<= x<= 1 ?
The extreme f(x)=-x-4,-4<= x<= 1 is Maximum(-4,0),Minimum(1,-5)