What is the extreme f(x)=x+(2*1800)/x ?

The extreme f(x)=x+(2*1800)/x is Maximum(-60,-120),Minimum(60,120)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x+(2*1800)/x

extreme points

f (x) = x + \frac{2 \cdot 1800}{x}

Maximum (- 60, - 120), Minimum (60, 120)

Solution steps

f^{'} (x) = 1 - \frac{3600}{x ^{2}}

Find intervals:

Increasing

: - \infty < x < - 60,

Decreasing

: - 60 < x < 0,

Decreasing

: 0 < x < 60,

Increasing

: 60 < x < \infty

Plug

x = - 60

into

x + \frac{2 \cdot 1800}{x} : - 120

Maximum (- 60, - 120)

Plug

x = 60

into

x + \frac{2 \cdot 1800}{x} : 120

Minimum (60, 120)

Maximum (- 60, - 120), Minimum (60, 120)

f (x) = 4 x^{3} - 4 x^{2} - 4 x + 5

f (x) = 4 x^{3} - 4 x^{2} - 4 x + 7

3.79254 E 84

y = \frac{4}{x} + x

x \cdot 4 - x^{2}

What is the extreme f(x)=x+(2*1800)/x ?
The extreme f(x)=x+(2*1800)/x is Maximum(-60,-120),Minimum(60,120)