What is the extreme f(x,y)=x^2-y^2+21 ?

The extreme f(x,y)=x^2-y^2+21 is Saddle(0,0)

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extreme f(x,y)=x^2-y^2+21

extreme points

f (x, y) = x^{2} - y^{2} + 21

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = - 4

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

- \frac{5 e ^{4 x}}{x - 4}

f (x, y) = x - k y

f (x) = \frac{x + 3}{x ^{2} - 2 x - 15}

f (x) = x^{2} (e^{- x^{2}})

Z (p, q) = p^{2} + q^{2}

What is the extreme f(x,y)=x^2-y^2+21 ?
The extreme f(x,y)=x^2-y^2+21 is Saddle(0,0)