en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=9x^2+3[-1.2]

Solution

extreme points

f (x) = 9 x^{2} + 3 [- 1.2]

Solution

Minimum (0, - 3.6)

Solution steps

f^{'} (x) = 18 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

9 x^{2} + 3 [- 1.2] : - 3.6

Minimum (0, - 3.6)

Popular Examples

extreme f(x)=-2x^3-13 extreme points

f (x) = - 2 x^{3} - 13

extreme f(x)=9-4x-3x^2,-2<= x<= 1 extreme points

f (x) = 9 - 4 x - 3 x^{2}, - 2 \leq x \leq 1

extreme f(x)=3x^2+12x-9 extreme points

f (x) = 3 x^{2} + 12 x - 9

extreme f(x)=395x^2-3160x^3 extreme points

f (x) = 395 x^{2} - 3160 x^{3}

extreme e^{x-1}extreme points

e^{x - 1}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=9x^2+3[-1.2] ?
The extreme f(x)=9x^2+3[-1.2] is Minimum(0,-3.6)