What is the extreme y=0.25t^4-4.5t^2 ?

The extreme y=0.25t^4-4.5t^2 is Minimum(-3,-20.25),Maximum(0,0),Minimum(3,-20.25)

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extreme y=0.25t^4-4.5t^2

extreme points

y = 0.25 t^{4} - 4.5 t^{2}

Minimum (- 3, - 20.25), Maximum (0, 0), Minimum (3, - 20.25)

Solution steps

f^{'} (t) = t^{3} - 9 t

Find intervals:

Decreasing

: - \infty < t < - 3,

Increasing

: - 3 < t < 0,

Decreasing

: 0 < t < 3,

Increasing

: 3 < t < \infty

Plug

t = - 3

into

0.25 t^{4} - 4.5 t^{2} : - 20.25

Minimum (- 3, - 20.25)

Plug

t = 0

into

0.25 t^{4} - 4.5 t^{2} : 0

Maximum (0, 0)

Plug

t = 3

into

0.25 t^{4} - 4.5 t^{2} : - 20.25

Minimum (3, - 20.25)

Minimum (- 3, - 20.25), Maximum (0, 0), Minimum (3, - 20.25)

y = 10 x - 11 z

f (x) = 3 x^{2} + 12 x + \frac{7}{8}

f (x) = (x^{3} - 64)^{4}

f (x, y) = 7 x^{2} + 7 x y + 10 y^{2} + 7 x y^{2} + 4 x^{2} y

\frac{3}{x} - 1

What is the extreme y=0.25t^4-4.5t^2 ?
The extreme y=0.25t^4-4.5t^2 is Minimum(-3,-20.25),Maximum(0,0),Minimum(3,-20.25)