What is the extreme f(x,y)=e^{x*y}+1 ?

The extreme f(x,y)=e^{x*y}+1 is Saddle(0,0)

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extreme f(x,y)=e^{x*y}+1

extreme points

f (x, y) = e^{x \cdot y} + 1

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = e^{x y} x^{2}

D (x, y) = - 2 e^{2 x y} x y - e^{2 x y}

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

x^{2} + y^{2} - 12 x + 14 y - 6

f (x) = 2 n

\frac{0.002 x ^{3} + 9 x + 7626}{x}

3 x^{4} - 4 x^{3} + 6

x^{- 2} - 13 x^{- 1}

What is the extreme f(x,y)=e^{x*y}+1 ?
The extreme f(x,y)=e^{x*y}+1 is Saddle(0,0)