What is the extreme f(x)=(x^3)/3-375x^2+129600x ?

The extreme f(x)=(x^3)/3-375x^2+129600x is Maximum(270,14215500),Minimum(480,12672000)

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extreme f(x)=(x^3)/3-375x^2+129600x

extreme points

f (x) = \frac{x ^{3}}{3} - 375 x^{2} + 129600 x

Maximum (270, 14215500), Minimum (480, 12672000)

Solution steps

f^{'} (x) = x^{2} - 750 x + 129600

Find intervals:

Increasing

: - \infty < x < 270,

Decreasing

: 270 < x < 480,

Increasing

: 480 < x < \infty

Plug

x = 270

into

\frac{x ^{3}}{3} - 375 x^{2} + 129600 x : 14215500

Maximum (270, 14215500)

Plug

x = 480

into

\frac{x ^{3}}{3} - 375 x^{2} + 129600 x : 12672000

Minimum (480, 12672000)

Maximum (270, 14215500), Minimum (480, 12672000)

f (x) = e^{4 x - x^{2}}

f (x, y) = x^{2} + 4 y^{2} - 6 x + 8 y + 2

f (x, y) = x^{2} - y^{2} + 9

(x + 3)^{2} + 1

y = \frac{x ^{2} - 2 x + 1}{x ^{2} + 3}

What is the extreme f(x)=(x^3)/3-375x^2+129600x ?
The extreme f(x)=(x^3)/3-375x^2+129600x is Maximum(270,14215500),Minimum(480,12672000)