en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme (x+3)^2+1

Solution

extreme points

(x + 3)^{2} + 1

Solution

Minimum (- 3, 1)

Solution steps

f^{'} (x) = 2 x + 6

Find intervals:

Decreasing

: - \infty < x < - 3,

Increasing

: - 3 < x < \infty

Plug

x = - 3

into

(x + 3)^{2} + 1 : 1

Minimum (- 3, 1)

Popular Examples

extreme y=(x^2-2x+1)/(x^2+3)extreme points

y = \frac{x ^{2} - 2 x + 1}{x ^{2} + 3}

extreme f(x)=(7+x)(11-3x)^{1/3}extreme points

f (x) = (7 + x) (11 - 3 x)^{\frac{1}{3}}

extreme y=x^{-4}*e^{x^4}extreme points

y = x^{- 4} \cdot e^{x^{4}}

extreme f(x)=-2x^3+12 extreme points

f (x) = - 2 x^{3} + 12

extreme f(x)=-2x^2+3x-4 extreme points

f (x) = - 2 x^{2} + 3 x - 4

Frequently Asked Questions (FAQ)

What is the extreme (x+3)^2+1 ?
The extreme (x+3)^2+1 is Minimum(-3,1)