What is the extreme f(x)=540x-5x^3 ?

The extreme f(x)=540x-5x^3 is Minimum(-6,-2160),Maximum(6,2160)

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extreme f(x)=540x-5x^3

extreme points

f (x) = 540 x - 5 x^{3}

Minimum (- 6, - 2160), Maximum (6, 2160)

Solution steps

f^{'} (x) = 540 - 15 x^{2}

Find intervals:

Decreasing

: - \infty < x < - 6,

Increasing

: - 6 < x < 6,

Decreasing

: 6 < x < \infty

Plug

x = - 6

into

540 x - 5 x^{3} : - 2160

Minimum (- 6, - 2160)

Plug

x = 6

into

540 x - 5 x^{3} : 2160

Maximum (6, 2160)

Minimum (- 6, - 2160), Maximum (6, 2160)

120 x + 120 y - x y - x^{2} - y^{2}

f (x) = 500 \cdot 2^{4 x}

f (x, y) = x 1 + y^{(3)}

f (x) = (x + 6) (x + 8)^{2}

f (x) = - \frac{4}{3} x^{3} - \frac{21}{2} x^{2} - 5 x + 14

What is the extreme f(x)=540x-5x^3 ?
The extreme f(x)=540x-5x^3 is Minimum(-6,-2160),Maximum(6,2160)