What is the extreme f(x)=(x+6)(x+8)^2 ?

The extreme f(x)=(x+6)(x+8)^2 is Maximum(-8,0),Minimum(-20/3 ,-32/27)

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extreme f(x)=(x+6)(x+8)^2

extreme points

f (x) = (x + 6) (x + 8)^{2}

Maximum (- 8, 0), Minimum (- \frac{20}{3}, - \frac{32}{27})

Solution steps

f^{'} (x) = (x + 8) (3 x + 20)

Find intervals:

Increasing

: - \infty < x < - 8,

Decreasing

: - 8 < x < - \frac{20}{3},

Increasing

: - \frac{20}{3} < x < \infty

Plug

x = - 8

into

(x + 6) (x + 8)^{2} : 0

Maximum (- 8, 0)

Plug

x = - \frac{20}{3}

into

(x + 6) (x + 8)^{2} : - \frac{32}{27}

Minimum (- \frac{20}{3}, - \frac{32}{27})

Maximum (- 8, 0), Minimum (- \frac{20}{3}, - \frac{32}{27})

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f (x, y) = x^{2} + x y + y^{2} - 10 y + 33

f (x) = x^{\frac{1}{5}} (x - 2)

f (x) = \frac{( x ^{2} )}{x - 2}

f (x) = \frac{( 7 ln ( x ) + 4 )}{x}

What is the extreme f(x)=(x+6)(x+8)^2 ?
The extreme f(x)=(x+6)(x+8)^2 is Maximum(-8,0),Minimum(-20/3 ,-32/27)