What is the extreme f(x)=-2x^3+42x^2-270x+3 ?

The extreme f(x)=-2x^3+42x^2-270x+3 is Minimum(5,-547),Maximum(9,-483)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=-2x^3+42x^2-270x+3

extreme points

f (x) = - 2 x^{3} + 42 x^{2} - 270 x + 3

Minimum (5, - 547), Maximum (9, - 483)

Solution steps

f^{'} (x) = - 6 x^{2} + 84 x - 270

Find intervals:

Decreasing

: - \infty < x < 5,

Increasing

: 5 < x < 9,

Decreasing

: 9 < x < \infty

Plug

x = 5

into

- 2 x^{3} + 42 x^{2} - 270 x + 3 : - 547

Minimum (5, - 547)

Plug

x = 9

into

- 2 x^{3} + 42 x^{2} - 270 x + 3 : - 483

Maximum (9, - 483)

Minimum (5, - 547), Maximum (9, - 483)

f (x) = - 2 x^{3} + 42 x^{2} - 270 x + 8

x^{4} - y^{4} - 2 x^{2} + 2 y^{2}

f (x) = \frac{x}{8 x - 3}, 8 \leq x \leq 13

f (x, y) = x^{2} + \frac{5}{2}

f (x) = \frac{x}{( x - 7 ) ^{2}}

What is the extreme f(x)=-2x^3+42x^2-270x+3 ?
The extreme f(x)=-2x^3+42x^2-270x+3 is Minimum(5,-547),Maximum(9,-483)