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Popular >

extreme f(x,y)=x^2+5/2

Solution

extreme points

f (x, y) = x^{2} + \frac{5}{2}

Solution

Minimum (0, \frac{5}{2})

Solution steps

f^{'} (x) = 2 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{2} + \frac{5}{2} : \frac{5}{2}

Minimum (0, \frac{5}{2})

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Frequently Asked Questions (FAQ)

What is the extreme f(x,y)=x^2+5/2 ?
The extreme f(x,y)=x^2+5/2 is Minimum(0, 5/2)