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Popular >

extreme g(t)=t^4+t^3+t^2+1

Solution

extreme points

g (t) = t^{4} + t^{3} + t^{2} + 1

Solution

Minimum (0, 1)

Solution steps

f^{'} (t) = 4 t^{3} + 3 t^{2} + 2 t

Find intervals:

Decreasing

: - \infty < t < 0,

Increasing

: 0 < t < \infty

Plug

t = 0

into

t^{4} + t^{3} + t^{2} + 1 : 1

Minimum (0, 1)

Popular Examples

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f (x, y) = (x + y)^{3} - 12 x y

extreme f(x_{1},x_{2})=x_{1}+x_{1}x_{2}+x_{2}extreme points

f (x_{1}, x_{2}) = x_{1} + x_{1} x_{2} + x_{2}

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f (x) = (x - 2)^{2} - 1

extreme f(x)=395x^2-2920x^3 extreme points

f (x) = 395 x^{2} - 2920 x^{3}

Frequently Asked Questions (FAQ)

What is the extreme g(t)=t^4+t^3+t^2+1 ?
The extreme g(t)=t^4+t^3+t^2+1 is Minimum(0,1)