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Popular >

extreme f(x)=-2x^2+8x

Solution

extreme points

f (x) = - 2 x^{2} + 8 x

Solution

Maximum (2, 8)

Solution steps

f^{'} (x) = - 4 x + 8

Find intervals:

Increasing

: - \infty < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = 2

into

- 2 x^{2} + 8 x : 8

Maximum (2, 8)

Popular Examples

extreme f(x)=3-3x^2,-5<= x<= 2 extreme points

f (x) = 3 - 3 x^{2}, - 5 \leq x \leq 2

extreme f(x)= 2/(5x^2+1),-2<= x<= 5 extreme points

f (x) = \frac{2}{5 x ^{2} + 1}, - 2 \leq x \leq 5

extreme f(x)=-1.872x^2+33.792-102.353 extreme points

f (x) = - 1.872 x^{2} + 33.792 - 102.353

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f (x) = cos^{(2)} (x) - 2 sin (x)

extreme x^3+y^4-9x-16y^2 extreme points

x^{3} + y^{4} - 9 x - 16 y^{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-2x^2+8x ?
The extreme f(x)=-2x^2+8x is Maximum(2,8)