What is the extreme f(x)=(41000-5000x)(2.5+0.5x) ?

The extreme f(x)=(41000-5000x)(2.5+0.5x) is Maximum(8/5 ,108900)

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extreme f(x)=(41000-5000x)(2.5+0.5x)

extreme points

f (x) = (41000 - 5000 x) (2.5 + 0.5 x)

Maximum (\frac{8}{5}, 108900)

Solution steps

f^{'} (x) = - 1000 (5 x - 8)

Find intervals:

Increasing

: - \infty < x < \frac{8}{5},

Decreasing

: \frac{8}{5} < x < \infty

Plug

x = \frac{8}{5}

into

(41000 - 5000 x) (2.5 + 0.5 x) : 108900

Maximum (\frac{8}{5}, 108900)

f (x) = - 12 x + 30

x^{3} + 15 x^{2}

f (x) = 60 x^{4} - 60 x^{3} - 60 x^{2}

f (x) = \frac{5 x}{( 3 x - 2 ) ^{2}}

f (x) = (- 16 + 2 x) (\frac{39}{2} - x) x

What is the extreme f(x)=(41000-5000x)(2.5+0.5x) ?
The extreme f(x)=(41000-5000x)(2.5+0.5x) is Maximum(8/5 ,108900)