en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=(-x^2)/(x^2-4)

Solution

extreme points

f (x) = \frac{- x ^{2}}{x ^{2} - 4}

Solution

Minimum (0, 0)

Solution steps

f^{'} (x) = \frac{8 x}{( x ^{2} - 4 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 0,

Increasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 0

into

\frac{- x ^{2}}{x ^{2} - 4} : 0

Minimum (0, 0)

Popular Examples

extreme y= x/(sqrt(x^2+3))extreme points

y = \frac{x}{x ^{2} + 3}

extreme y=x^2-8x,-infinity <= x<= 8 extreme points

y = x^{2} - 8 x, - \infty \leq x \leq 8

extreme f(x)=28x^{1/2}-x extreme points

f (x) = 28 x^{\frac{1}{2}} - x

extreme f(x)=-27x^2+504x extreme points

f (x) = - 27 x^{2} + 504 x

extreme f(x)=2xsqrt(225-x^2)extreme points

f (x) = 2 x 225 - x^{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(-x^2)/(x^2-4) ?
The extreme f(x)=(-x^2)/(x^2-4) is Minimum(0,0)