What is the extreme f(x)=x^3-2x^2-4x+2[-1] ?

The extreme f(x)=x^3-2x^2-4x+2[-1] is Maximum(-2/3 ,-14/27),Minimum(2,-10)

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extreme f(x)=x^3-2x^2-4x+2[-1]

extreme points

f (x) = x^{3} - 2 x^{2} - 4 x + 2 [- 1]

Maximum (- \frac{2}{3}, - \frac{14}{27}), Minimum (2, - 10)

Solution steps

f^{'} (x) = 3 x^{2} - 4 x - 4

Find intervals:

Increasing

: - \infty < x < - \frac{2}{3},

Decreasing

: - \frac{2}{3} < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - \frac{2}{3}

into

x^{3} - 2 x^{2} - 4 x + 2 [- 1] : - \frac{14}{27}

Maximum (- \frac{2}{3}, - \frac{14}{27})

Plug

x = 2

into

x^{3} - 2 x^{2} - 4 x + 2 [- 1] : - 10

Minimum (2, - 10)

Maximum (- \frac{2}{3}, - \frac{14}{27}), Minimum (2, - 10)

x^{2} - 6 x y + y^{3} + 24 y + 7

f (x) = e^{x^{2} + y^{2} + 2 x}

f (x) = 1 + (x + 1)^{2}

4 x^{2} - 2 x + 11

6 x y - x^{3} - 3 y^{2}

What is the extreme f(x)=x^3-2x^2-4x+2[-1] ?
The extreme f(x)=x^3-2x^2-4x+2[-1] is Maximum(-2/3 ,-14/27),Minimum(2,-10)