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Popular >

extreme f(x)=4x^2-5x+1

Solution

extreme points

f (x) = 4 x^{2} - 5 x + 1

Solution

Minimum (\frac{5}{8}, - \frac{9}{16})

Solution steps

f^{'} (x) = 8 x - 5

Find intervals:

Decreasing

: - \infty < x < \frac{5}{8},

Increasing

: \frac{5}{8} < x < \infty

Plug

x = \frac{5}{8}

into

4 x^{2} - 5 x + 1 : - \frac{9}{16}

Minimum (\frac{5}{8}, - \frac{9}{16})

Popular Examples

extreme f(x)=x^3-4x^2-3x+6 extreme points

f (x) = x^{3} - 4 x^{2} - 3 x + 6

extreme f(x)=x^3-4x^2-3x+8 extreme points

f (x) = x^{3} - 4 x^{2} - 3 x + 8

extreme x^3-6 extreme points

x^{3} - 6

extreme 2x^3-6x^2+6x+1 extreme points

2 x^{3} - 6 x^{2} + 6 x + 1

extreme x*e^x extreme points

x \cdot e^{x}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=4x^2-5x+1 ?
The extreme f(x)=4x^2-5x+1 is Minimum(5/8 ,-9/16)