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Popular >

extreme f(x)=12x^2-16

Solution

extreme points

f (x) = 12 x^{2} - 16

Solution

Minimum (0, - 16)

Solution steps

f^{'} (x) = 24 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

12 x^{2} - 16 : - 16

Minimum (0, - 16)

Popular Examples

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2 x^{3} - 6 x^{2} - 210 x + 7

extreme f(x,y)=2x^2-8y^2-13 extreme points

f (x, y) = 2 x^{2} - 8 y^{2} - 13

extreme f(x)=2x-5x^{2/5}extreme points

f (x) = 2 x - 5 x^{\frac{2}{5}}

extreme y=-x^2+5,(-2,4)extreme points

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extreme f(x)=4sin(x)+3cos(x)extreme points

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=12x^2-16 ?
The extreme f(x)=12x^2-16 is Minimum(0,-16)