What is the extreme f(x)=-2xy-8x^2-2y^2-86x+8y+9 ?

The extreme f(x)=-2xy-8x^2-2y^2-86x+8y+9 is Maximum(-6,5)

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extreme f(x)=-2xy-8x^2-2y^2-86x+8y+9

extreme points

f (x) = - 2 x y - 8 x^{2} - 2 y^{2} - 86 x + 8 y + 9

Maximum (- 6, 5)

Solution steps

Find the critical points:

(- 6, 5)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 4

D (x, y) = 60

Check the sign of at each critical point

Check critical point

(- 6, 5) :

Maximum

Maximum (- 6, 5)

y = 2 x + sin (4 x), - \frac{π}{3} \leq x \leq \frac{π}{3}

x^{2} + 10 x + 24

x^{2} + 4 x - 1

f (x) = 2 x^{3} - 6 x + 3, - 2 \leq x \leq 2

What is the extreme f(x)=-2xy-8x^2-2y^2-86x+8y+9 ?
The extreme f(x)=-2xy-8x^2-2y^2-86x+8y+9 is Maximum(-6,5)