What is the extreme 2x^2y+xy^2-x ?

The extreme 2x^2y+xy^2-x is Saddle(0,1),Saddle(0,-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme 2x^2y+xy^2-x

extreme points

2 x^{2} y + x y^{2} - x

Saddle (0, 1), Saddle (0, - 1)

Solution steps

Find the critical points:

(0, 1), (0, - 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = 2 x

D (x, y) = - 16 x^{2} - 8 x y - 4 y^{2}

Check the sign of at each critical point

Check critical point

(0, 1) :

Saddle

Check critical point

(0, - 1) :

Saddle

Saddle (0, 1), Saddle (0, - 1)

f (x) = x + x - 1

f (x) = x + 4 y

f (x) = x^{2} + \frac{5}{2}

f (x) = \frac{1}{x - 8}

f (x) = x + 6 x

What is the extreme 2x^2y+xy^2-x ?
The extreme 2x^2y+xy^2-x is Saddle(0,1),Saddle(0,-1)