What is x+f(x)=x^2+13 ?

The solution to x+f(x)=x^2+13 is Parabola with (h,k)=(1/2 , 51/4),p= 1/4

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x+f(x)=x^2+13

x + f (x) = x^{2} + 13

(h, k) = (\frac{1}{2}, \frac{51}{4}), p = \frac{1}{4}

Solution steps

x + y = x^{2} + 13

Rewrite

x + y = x^{2} + 13

in the standard form

4 \cdot \frac{1}{4} (y - \frac{51}{4}) = (x - \frac{1}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{2}, \frac{51}{4}), p = \frac{1}{4}

f (x) = 2 (x)^{2} - 4 (x)

f (x) = 3 x - 1

f (x) = (60 - 2 x) (30 - x) x

f (x) = f (x) = 3 x - x^{3}

f (x) = \frac{1}{x ^{2} + 4}

What is x+f(x)=x^2+13 ?
The solution to x+f(x)=x^2+13 is Parabola with (h,k)=(1/2 , 51/4),p= 1/4