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Popular >

extreme f(x)= 1/(x^2+4)

Solution

extreme points

f (x) = \frac{1}{x ^{2} + 4}

Solution

Maximum (0, \frac{1}{4})

Solution steps

f^{'} (x) = - \frac{2 x}{( x ^{2} + 4 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = 0

into

\frac{1}{x ^{2} + 4} : \frac{1}{4}

Maximum (0, \frac{1}{4})

Popular Examples

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y = - x^{2} + 25

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f (x) = 3 + 7 x + 175 x^{- 1}

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\frac{1}{x ^{2} - x - 6}

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extreme f(x)=4x^3-46x^2+120x extreme points

f (x) = 4 x^{3} - 46 x^{2} + 120 x

Frequently Asked Questions (FAQ)

What is the extreme f(x)= 1/(x^2+4) ?
The extreme f(x)= 1/(x^2+4) is Maximum(0, 1/4)