What is the extreme f(xy)=y^2ln(x^2y) ?

The extreme f(xy)=y^2ln(x^2y) is None

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extreme f(xy)=y^2ln(x^2y)

extreme points

f (x y) = y^{2} ln (x^{2} y)

None

Solution steps

Find the critical points:

None

y^{2} ln (x^{2} y)

has no critical points, therefore there are no extreme points

None

f (x) = 2 x^{4} - 8 x

4 x^{3} - 12 x^{2} + 8 x

f (x) = 6 x^{2} - 6 x - 36

f (x) = \frac{( 1 + x )}{3 - x}

f (x) = 3 x - 100 - \frac{15}{1000} x^{2}