What is the extreme f(x,y)=10^{-4}y-2*10^{-8}y^2 ?

The extreme f(x,y)=10^{-4}y-2*10^{-8}y^2 is Maximum(2500, 1/8)

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extreme f(x,y)=10^{-4}y-2*10^{-8}y^2

extreme points

f (x, y) = 1 0^{- 4} y - 2 \cdot 1 0^{- 8} y^{2}

Maximum (2500, \frac{1}{8})

Solution steps

f^{'} (y) = \frac{1}{10000} - \frac{y}{25000000}

Find intervals:

Increasing

: - \infty < y < 2500,

Decreasing

: 2500 < y < \infty

Plug

y = 2500

into

1 0^{- 4} y - 2 \cdot 1 0^{- 8} y^{2} : \frac{1}{8}

Maximum (2500, \frac{1}{8})

f (x) = - 4 x^{2} + 4 x - 3

f (x) = x^{2} lo g_{10} (2 x)

f (x) = - [x + 2]

f (x) = 2 x^{3} + 9 x^{2} - 24 x, - 5 \leq x \leq 2

22 x^{2}

What is the extreme f(x,y)=10^{-4}y-2*10^{-8}y^2 ?
The extreme f(x,y)=10^{-4}y-2*10^{-8}y^2 is Maximum(2500, 1/8)