What is the extreme y=4x+8((20000)/x) ?

The extreme y=4x+8((20000)/x) is Maximum(-200,-1600),Minimum(200,1600)

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extreme y=4x+8((20000)/x)

extreme points

y = 4 x + 8 (\frac{20000}{x})

Maximum (- 200, - 1600), Minimum (200, 1600)

Solution steps

f^{'} (x) = 4 - \frac{160000}{x ^{2}}

Find intervals:

Increasing

: - \infty < x < - 200,

Decreasing

: - 200 < x < 0,

Decreasing

: 0 < x < 200,

Increasing

: 200 < x < \infty

Plug

x = - 200

into

4 x + 8 \frac{20000}{x} : - 1600

Maximum (- 200, - 1600)

Plug

x = 200

into

4 x + 8 \frac{20000}{x} : 1600

Minimum (200, 1600)

Maximum (- 200, - 1600), Minimum (200, 1600)

f (x) = (x^{2} + 4)^{2}

f (x) = 9 x^{2} - 72 x + 108

x^{4} + 3 x^{3} - 6

f (x, y) = x^{2} - 14 x + y^{2} - 16 y

f (x) = x^{3} - 5 x + 4

What is the extreme y=4x+8((20000)/x) ?
The extreme y=4x+8((20000)/x) is Maximum(-200,-1600),Minimum(200,1600)