What is the extreme f(x,y)=-3x^2+2y^2 ?

The extreme f(x,y)=-3x^2+2y^2 is Saddle(0,0)

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extreme f(x,y)=-3x^2+2y^2

extreme points

f (x, y) = - 3 x^{2} + 2 y^{2}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = 4

D (x, y) = - 24

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

+ 2.5 t^{2} + 6 t

f (x) = 8 x^{3} - 6 x^{2}

f (x) = e^{- 2 x^{2}} - 3 y^{2} + 2 y

f (x) = 3 x^{2} - 12 x + 2

f (x) = x^{4} - 8 x + 4

What is the extreme f(x,y)=-3x^2+2y^2 ?
The extreme f(x,y)=-3x^2+2y^2 is Saddle(0,0)