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Popular >

extreme f(x)=sqrt(8-x)

Solution

extreme points

f (x) = 8 - x

Solution

Minimum (8, 0)

Solution steps

f^{'} (x) = - \frac{1}{2 8 - x}

Find intervals:

Decreasing

: - \infty < x < 8

Plug

x = 8

into

8 - x : 0

Minimum (8, 0)

Popular Examples

extreme f(x)=6+81x-3x^3,0<= x<= 4 extreme points

f (x) = 6 + 81 x - 3 x^{3}, 0 \leq x \leq 4

extreme f(x)=(x^2+69)/(x+10)extreme points

f (x) = \frac{x ^{2} + 69}{x + 10}

extreme (t^2)/(t+3)extreme points

\frac{t ^{2}}{t + 3}

extreme f(x)=x^3-10x+25x-2 extreme points

f (x) = x^{3} - 10 x + 25 x - 2

extreme f(x)=(20)/x+2pix^2,x>0 extreme points

f (x) = \frac{20}{x} + 2 π x^{2}, x > 0

Frequently Asked Questions (FAQ)

What is the extreme f(x)=sqrt(8-x) ?
The extreme f(x)=sqrt(8-x) is Minimum(8,0)