What is the extreme f(x)=(x^2-10x+25)/(x-8) ?

The extreme f(x)=(x^2-10x+25)/(x-8) is Maximum(5,0),Minimum(11,12)

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extreme f(x)=(x^2-10x+25)/(x-8)

extreme points

f (x) = \frac{x ^{2} - 10 x + 25}{x - 8}

Maximum (5, 0), Minimum (11, 12)

Solution steps

f^{'} (x) = \frac{x ^{2} - 16 x + 55}{( x - 8 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 5,

Decreasing

: 5 < x < 8,

Decreasing

: 8 < x < 11,

Increasing

: 11 < x < \infty

Plug

x = 5

into

\frac{x ^{2} - 10 x + 25}{x - 8} : 0

Maximum (5, 0)

Plug

x = 11

into

\frac{x ^{2} - 10 x + 25}{x - 8} : 12

Minimum (11, 12)

Maximum (5, 0), Minimum (11, 12)

f (x) = \frac{- 2}{3} x^{3} + 10 x^{2} - 48 x - 1

x^{\frac{2}{3}} (x^{3} - 44)

2 x^{2} + 16 x - 4

\frac{x ^{5}}{20} - 3 x^{3}

g (x, y) = 2 x^{2} - y^{2}

What is the extreme f(x)=(x^2-10x+25)/(x-8) ?
The extreme f(x)=(x^2-10x+25)/(x-8) is Maximum(5,0),Minimum(11,12)